Optimal. Leaf size=95 \[ -\frac{c^3 \left (1-a^2 x^2\right )^{7/2}}{a \sin ^{-1}(a x)}-\frac{35 c^3 \text{Si}\left (\sin ^{-1}(a x)\right )}{64 a}-\frac{63 c^3 \text{Si}\left (3 \sin ^{-1}(a x)\right )}{64 a}-\frac{35 c^3 \text{Si}\left (5 \sin ^{-1}(a x)\right )}{64 a}-\frac{7 c^3 \text{Si}\left (7 \sin ^{-1}(a x)\right )}{64 a} \]
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Rubi [A] time = 0.17414, antiderivative size = 95, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 4, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {4659, 4723, 4406, 3299} \[ -\frac{c^3 \left (1-a^2 x^2\right )^{7/2}}{a \sin ^{-1}(a x)}-\frac{35 c^3 \text{Si}\left (\sin ^{-1}(a x)\right )}{64 a}-\frac{63 c^3 \text{Si}\left (3 \sin ^{-1}(a x)\right )}{64 a}-\frac{35 c^3 \text{Si}\left (5 \sin ^{-1}(a x)\right )}{64 a}-\frac{7 c^3 \text{Si}\left (7 \sin ^{-1}(a x)\right )}{64 a} \]
Antiderivative was successfully verified.
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Rule 4659
Rule 4723
Rule 4406
Rule 3299
Rubi steps
\begin{align*} \int \frac{\left (c-a^2 c x^2\right )^3}{\sin ^{-1}(a x)^2} \, dx &=-\frac{c^3 \left (1-a^2 x^2\right )^{7/2}}{a \sin ^{-1}(a x)}-\left (7 a c^3\right ) \int \frac{x \left (1-a^2 x^2\right )^{5/2}}{\sin ^{-1}(a x)} \, dx\\ &=-\frac{c^3 \left (1-a^2 x^2\right )^{7/2}}{a \sin ^{-1}(a x)}-\frac{\left (7 c^3\right ) \operatorname{Subst}\left (\int \frac{\cos ^6(x) \sin (x)}{x} \, dx,x,\sin ^{-1}(a x)\right )}{a}\\ &=-\frac{c^3 \left (1-a^2 x^2\right )^{7/2}}{a \sin ^{-1}(a x)}-\frac{\left (7 c^3\right ) \operatorname{Subst}\left (\int \left (\frac{5 \sin (x)}{64 x}+\frac{9 \sin (3 x)}{64 x}+\frac{5 \sin (5 x)}{64 x}+\frac{\sin (7 x)}{64 x}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{a}\\ &=-\frac{c^3 \left (1-a^2 x^2\right )^{7/2}}{a \sin ^{-1}(a x)}-\frac{\left (7 c^3\right ) \operatorname{Subst}\left (\int \frac{\sin (7 x)}{x} \, dx,x,\sin ^{-1}(a x)\right )}{64 a}-\frac{\left (35 c^3\right ) \operatorname{Subst}\left (\int \frac{\sin (x)}{x} \, dx,x,\sin ^{-1}(a x)\right )}{64 a}-\frac{\left (35 c^3\right ) \operatorname{Subst}\left (\int \frac{\sin (5 x)}{x} \, dx,x,\sin ^{-1}(a x)\right )}{64 a}-\frac{\left (63 c^3\right ) \operatorname{Subst}\left (\int \frac{\sin (3 x)}{x} \, dx,x,\sin ^{-1}(a x)\right )}{64 a}\\ &=-\frac{c^3 \left (1-a^2 x^2\right )^{7/2}}{a \sin ^{-1}(a x)}-\frac{35 c^3 \text{Si}\left (\sin ^{-1}(a x)\right )}{64 a}-\frac{63 c^3 \text{Si}\left (3 \sin ^{-1}(a x)\right )}{64 a}-\frac{35 c^3 \text{Si}\left (5 \sin ^{-1}(a x)\right )}{64 a}-\frac{7 c^3 \text{Si}\left (7 \sin ^{-1}(a x)\right )}{64 a}\\ \end{align*}
Mathematica [A] time = 0.58046, size = 83, normalized size = 0.87 \[ -\frac{c^3 \left (64 \left (1-a^2 x^2\right )^{7/2}+35 \sin ^{-1}(a x) \text{Si}\left (\sin ^{-1}(a x)\right )+63 \sin ^{-1}(a x) \text{Si}\left (3 \sin ^{-1}(a x)\right )+35 \sin ^{-1}(a x) \text{Si}\left (5 \sin ^{-1}(a x)\right )+7 \sin ^{-1}(a x) \text{Si}\left (7 \sin ^{-1}(a x)\right )\right )}{64 a \sin ^{-1}(a x)} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.05, size = 105, normalized size = 1.1 \begin{align*} -{\frac{{c}^{3}}{64\,a\arcsin \left ( ax \right ) } \left ( 35\,{\it Si} \left ( \arcsin \left ( ax \right ) \right ) \arcsin \left ( ax \right ) +63\,{\it Si} \left ( 3\,\arcsin \left ( ax \right ) \right ) \arcsin \left ( ax \right ) +35\,{\it Si} \left ( 5\,\arcsin \left ( ax \right ) \right ) \arcsin \left ( ax \right ) +7\,{\it Si} \left ( 7\,\arcsin \left ( ax \right ) \right ) \arcsin \left ( ax \right ) +\cos \left ( 7\,\arcsin \left ( ax \right ) \right ) +21\,\cos \left ( 3\,\arcsin \left ( ax \right ) \right ) +7\,\cos \left ( 5\,\arcsin \left ( ax \right ) \right ) +35\,\sqrt{-{a}^{2}{x}^{2}+1} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{7 \, a \arctan \left (a x, \sqrt{a x + 1} \sqrt{-a x + 1}\right ) \int \frac{{\left (a^{5} c^{3} x^{5} - 2 \, a^{3} c^{3} x^{3} + a c^{3} x\right )} \sqrt{a x + 1} \sqrt{-a x + 1}}{\arctan \left (a x, \sqrt{a x + 1} \sqrt{-a x + 1}\right )}\,{d x} -{\left (a^{6} c^{3} x^{6} - 3 \, a^{4} c^{3} x^{4} + 3 \, a^{2} c^{3} x^{2} - c^{3}\right )} \sqrt{a x + 1} \sqrt{-a x + 1}}{a \arctan \left (a x, \sqrt{a x + 1} \sqrt{-a x + 1}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{a^{6} c^{3} x^{6} - 3 \, a^{4} c^{3} x^{4} + 3 \, a^{2} c^{3} x^{2} - c^{3}}{\arcsin \left (a x\right )^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - c^{3} \left (\int \frac{3 a^{2} x^{2}}{\operatorname{asin}^{2}{\left (a x \right )}}\, dx + \int - \frac{3 a^{4} x^{4}}{\operatorname{asin}^{2}{\left (a x \right )}}\, dx + \int \frac{a^{6} x^{6}}{\operatorname{asin}^{2}{\left (a x \right )}}\, dx + \int - \frac{1}{\operatorname{asin}^{2}{\left (a x \right )}}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.40312, size = 128, normalized size = 1.35 \begin{align*} \frac{{\left (a^{2} x^{2} - 1\right )}^{3} \sqrt{-a^{2} x^{2} + 1} c^{3}}{a \arcsin \left (a x\right )} - \frac{7 \, c^{3} \operatorname{Si}\left (7 \, \arcsin \left (a x\right )\right )}{64 \, a} - \frac{35 \, c^{3} \operatorname{Si}\left (5 \, \arcsin \left (a x\right )\right )}{64 \, a} - \frac{63 \, c^{3} \operatorname{Si}\left (3 \, \arcsin \left (a x\right )\right )}{64 \, a} - \frac{35 \, c^{3} \operatorname{Si}\left (\arcsin \left (a x\right )\right )}{64 \, a} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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